11. Perhatikan gambar berikut! Panjang BC adalah....
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11. AE = 8 cm, EB = 4 cm, DE = 10 cm, CB = x cm
AB = AE + EB
= 8 + 4 = 12 cm
[tex] \frac{ae}{ab} = \frac{de}{cb} \\ \frac{8}{12} = \frac{10}{x} [/tex]
8x = 10.12
8x = 120
x = 120/8 = 15 cm
BC = x = 15 cm( C. )
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